A Blue Puck Has a Velocity of 3i –4j Ms Its Mass Is 20 Kg What Is Its Momentum
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Review - Explain this using one of Newton's Laws
A lead brick has a lot of mass
and therefore a lot of inertia.
The greater the mass, the greater the tendency for an object to remain at rest, the smaller the acceleration that is produced by a given force.
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Momentum Word Problems
Ex 1) A 5.0 kg mass has its velocity change from 8.0 m/s east to 2.0 m/s east.
Find the objects change in momentum.
Ex 1) A 5.0 kg mass has its velocity change from 8.0 m/s east to 2.0 m/s east. Find the objects change in momentum.
m = 5.0 kg
Vi = 8.0 m/s East
Vf = 2.0 m/s East
Δp = ?
Δp = mΔV
= (5.0 kg)(2.0 m/s - 8.0 m/s)
= -30. kgm/s East
or +30. kg m/s West
Ex 2) A 5.0 kg mass moving with a velocity of 8.0 m/s east has an impulse applied to it which causes its velocity to change to 20. m/s East. Find Impulse:
Ex 2) A 5.0 kg mass moving with a vector of 8.0 m/s east has an impulse applied to it which causes its velocity to change to 20. m/s East.
Find Impulse:
m = 5.0 kg
Vi = 8.0 m/s East
Vf = 20. m/s East
J = ?
J = mΔv = (5.0 kg)(12. m/s East)
= 60. kg m/s east
= 60. Ns East
Find the force if the impulse was applied for 3.0 sec.
F = ?
t = 3 seconds
m = 5.0 kg
Vi = 8.0 m/s East
Vf = 20. m/s East
J = 60. kg m/s east
J = Ft = 60. Ns East
F(3.0 sec) = 60. Ns East
F = 20. N East
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Ex 3) How long would it take for a net upward force of 100. N, to increase the speed of a 50. kg object from 100. m/s to 150. m/s.
Ex 3) How long would it take for a net upward force of 100. N, to increase the speed of a 50. kg object from 100. m/s to 150. m/s.
F = 100. N
m = 50. kg
Vi = 100. m/s
Vf = 150. m/s
t = ?
FΔt = mΔv
(100. N)t = 50. kg(50. m/s)
t = 25. secs
Ex 4) A 1.0 kg ball traveling @ 4.0 m/s strikes a wall and bounces straight back @ 2.0 m/s.
Find Δp
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Ex 4) A 1.0 kg ball traveling @ 4.0 m/s strikes a wall and bounces straight back @ 2.0 m/s.
Find Δp
m = 1.0 kg
Vi = 4.0 m/s
Vf = ?
Vf = -2.0 m/s
(opposite direction)
Δp = ?
(a) Δp = mΔv
= (1.0 kg)(-2.0 m/s - 4.0 m/s)
= - 6.0 kgm/s
(b) What is impulse applied to the ball?
J = Δp = -6.0 kgm/s
(c) What is impulse applied to the wall ?
J = +6.0 kgm/s
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AP Physics
p. 188) 17
Dp = mDv
Momentum only changes in the x direction
toward wall +
Vi = Vsinq
Vf = -Vsinq
Dp = mDv
D p = m(-2Vsinq )= 2.1 kgm/s left
Review
| A teacher pushed ice cubes of different masses with different amounts of force. Which diagram shows the cube that will show the biggest velocity change when pushed with the force represented by the arrow? | |
 | A) A |
[Law Of Conservation
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